7x^2+14x-560=0

Solution for 7x^2+14x-560=0 equation:

7x^2+14x-560=0

a = 7; b = 14; c = -560;
Δ = b2-4ac
Δ = 142-4·7·(-560)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-126}{2*7}=\frac{-140}{14}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+126}{2*7}=\frac{112}{14}
=8
$